Integrand size = 27, antiderivative size = 140 \[ \int \frac {a+b x+c x^2}{(d+e x)^2 \sqrt {f+g x}} \, dx=\frac {2 c \sqrt {f+g x}}{e^2 g}-\frac {\left (a+\frac {d (c d-b e)}{e^2}\right ) \sqrt {f+g x}}{(e f-d g) (d+e x)}+\frac {(c d (4 e f-3 d g)-e (2 b e f-b d g-a e g)) \text {arctanh}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{e^{5/2} (e f-d g)^{3/2}} \]
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Time = 0.17 (sec) , antiderivative size = 144, normalized size of antiderivative = 1.03, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.148, Rules used = {911, 1171, 396, 214} \[ \int \frac {a+b x+c x^2}{(d+e x)^2 \sqrt {f+g x}} \, dx=\frac {\text {arctanh}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) (c d (4 e f-3 d g)-e (-a e g-b d g+2 b e f))}{e^{5/2} (e f-d g)^{3/2}}-\frac {\sqrt {f+g x} \left (a e^2-b d e+c d^2\right )}{e^2 (d+e x) (e f-d g)}+\frac {2 c \sqrt {f+g x}}{e^2 g} \]
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Rule 214
Rule 396
Rule 911
Rule 1171
Rubi steps \begin{align*} \text {integral}& = \frac {2 \text {Subst}\left (\int \frac {\frac {c f^2-b f g+a g^2}{g^2}-\frac {(2 c f-b g) x^2}{g^2}+\frac {c x^4}{g^2}}{\left (\frac {-e f+d g}{g}+\frac {e x^2}{g}\right )^2} \, dx,x,\sqrt {f+g x}\right )}{g} \\ & = -\frac {\left (c d^2-b d e+a e^2\right ) \sqrt {f+g x}}{e^2 (e f-d g) (d+e x)}+\frac {\text {Subst}\left (\int \frac {-a+\frac {c d^2}{e^2}-\frac {b d}{e}-\frac {2 c f^2}{g^2}+\frac {2 b f}{g}+\frac {2 c (e f-d g) x^2}{e g^2}}{\frac {-e f+d g}{g}+\frac {e x^2}{g}} \, dx,x,\sqrt {f+g x}\right )}{e f-d g} \\ & = \frac {2 c \sqrt {f+g x}}{e^2 g}-\frac {\left (c d^2-b d e+a e^2\right ) \sqrt {f+g x}}{e^2 (e f-d g) (d+e x)}-\frac {(c d (4 e f-3 d g)-e (2 b e f-b d g-a e g)) \text {Subst}\left (\int \frac {1}{\frac {-e f+d g}{g}+\frac {e x^2}{g}} \, dx,x,\sqrt {f+g x}\right )}{e^2 g (e f-d g)} \\ & = \frac {2 c \sqrt {f+g x}}{e^2 g}-\frac {\left (c d^2-b d e+a e^2\right ) \sqrt {f+g x}}{e^2 (e f-d g) (d+e x)}+\frac {(c d (4 e f-3 d g)-e (2 b e f-b d g-a e g)) \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{e^{5/2} (e f-d g)^{3/2}} \\ \end{align*}
Time = 0.43 (sec) , antiderivative size = 150, normalized size of antiderivative = 1.07 \[ \int \frac {a+b x+c x^2}{(d+e x)^2 \sqrt {f+g x}} \, dx=\frac {\sqrt {f+g x} \left (e (b d-a e) g+c \left (-3 d^2 g+2 e^2 f x+2 d e (f-g x)\right )\right )}{e^2 g (e f-d g) (d+e x)}-\frac {(c d (-4 e f+3 d g)+e (2 b e f-b d g-a e g)) \arctan \left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {-e f+d g}}\right )}{e^{5/2} (-e f+d g)^{3/2}} \]
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Time = 0.55 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.09
method | result | size |
risch | \(\frac {2 c \sqrt {g x +f}}{e^{2} g}+\frac {\frac {g \left (e^{2} a -b d e +c \,d^{2}\right ) \sqrt {g x +f}}{\left (d g -e f \right ) \left (e \left (g x +f \right )+d g -e f \right )}+\frac {\left (a \,e^{2} g +b d e g -2 b \,e^{2} f -3 c \,d^{2} g +4 c d e f \right ) \arctan \left (\frac {e \sqrt {g x +f}}{\sqrt {\left (d g -e f \right ) e}}\right )}{\left (d g -e f \right ) \sqrt {\left (d g -e f \right ) e}}}{e^{2}}\) | \(152\) |
derivativedivides | \(\frac {\frac {2 c \sqrt {g x +f}}{e^{2}}+\frac {2 g \left (\frac {g \left (e^{2} a -b d e +c \,d^{2}\right ) \sqrt {g x +f}}{2 \left (d g -e f \right ) \left (e \left (g x +f \right )+d g -e f \right )}+\frac {\left (a \,e^{2} g +b d e g -2 b \,e^{2} f -3 c \,d^{2} g +4 c d e f \right ) \arctan \left (\frac {e \sqrt {g x +f}}{\sqrt {\left (d g -e f \right ) e}}\right )}{2 \left (d g -e f \right ) \sqrt {\left (d g -e f \right ) e}}\right )}{e^{2}}}{g}\) | \(156\) |
default | \(\frac {\frac {2 c \sqrt {g x +f}}{e^{2}}+\frac {2 g \left (\frac {g \left (e^{2} a -b d e +c \,d^{2}\right ) \sqrt {g x +f}}{2 \left (d g -e f \right ) \left (e \left (g x +f \right )+d g -e f \right )}+\frac {\left (a \,e^{2} g +b d e g -2 b \,e^{2} f -3 c \,d^{2} g +4 c d e f \right ) \arctan \left (\frac {e \sqrt {g x +f}}{\sqrt {\left (d g -e f \right ) e}}\right )}{2 \left (d g -e f \right ) \sqrt {\left (d g -e f \right ) e}}\right )}{e^{2}}}{g}\) | \(156\) |
pseudoelliptic | \(\frac {\left (e x +d \right ) g \left (\left (a g -2 b f \right ) e^{2}+d \left (b g +4 c f \right ) e -3 c \,d^{2} g \right ) \arctan \left (\frac {e \sqrt {g x +f}}{\sqrt {\left (d g -e f \right ) e}}\right )+\sqrt {g x +f}\, \sqrt {\left (d g -e f \right ) e}\, \left (\left (-2 c f x +a g \right ) e^{2}-d \left (\left (-2 c x +b \right ) g +2 c f \right ) e +3 c \,d^{2} g \right )}{\sqrt {\left (d g -e f \right ) e}\, g \,e^{2} \left (d g -e f \right ) \left (e x +d \right )}\) | \(156\) |
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Leaf count of result is larger than twice the leaf count of optimal. 312 vs. \(2 (126) = 252\).
Time = 0.49 (sec) , antiderivative size = 637, normalized size of antiderivative = 4.55 \[ \int \frac {a+b x+c x^2}{(d+e x)^2 \sqrt {f+g x}} \, dx=\left [-\frac {\sqrt {e^{2} f - d e g} {\left (2 \, {\left (2 \, c d^{2} e - b d e^{2}\right )} f g - {\left (3 \, c d^{3} - b d^{2} e - a d e^{2}\right )} g^{2} + {\left (2 \, {\left (2 \, c d e^{2} - b e^{3}\right )} f g - {\left (3 \, c d^{2} e - b d e^{2} - a e^{3}\right )} g^{2}\right )} x\right )} \log \left (\frac {e g x + 2 \, e f - d g - 2 \, \sqrt {e^{2} f - d e g} \sqrt {g x + f}}{e x + d}\right ) - 2 \, {\left (2 \, c d e^{3} f^{2} - {\left (5 \, c d^{2} e^{2} - b d e^{3} + a e^{4}\right )} f g + {\left (3 \, c d^{3} e - b d^{2} e^{2} + a d e^{3}\right )} g^{2} + 2 \, {\left (c e^{4} f^{2} - 2 \, c d e^{3} f g + c d^{2} e^{2} g^{2}\right )} x\right )} \sqrt {g x + f}}{2 \, {\left (d e^{5} f^{2} g - 2 \, d^{2} e^{4} f g^{2} + d^{3} e^{3} g^{3} + {\left (e^{6} f^{2} g - 2 \, d e^{5} f g^{2} + d^{2} e^{4} g^{3}\right )} x\right )}}, -\frac {\sqrt {-e^{2} f + d e g} {\left (2 \, {\left (2 \, c d^{2} e - b d e^{2}\right )} f g - {\left (3 \, c d^{3} - b d^{2} e - a d e^{2}\right )} g^{2} + {\left (2 \, {\left (2 \, c d e^{2} - b e^{3}\right )} f g - {\left (3 \, c d^{2} e - b d e^{2} - a e^{3}\right )} g^{2}\right )} x\right )} \arctan \left (\frac {\sqrt {-e^{2} f + d e g} \sqrt {g x + f}}{e g x + e f}\right ) - {\left (2 \, c d e^{3} f^{2} - {\left (5 \, c d^{2} e^{2} - b d e^{3} + a e^{4}\right )} f g + {\left (3 \, c d^{3} e - b d^{2} e^{2} + a d e^{3}\right )} g^{2} + 2 \, {\left (c e^{4} f^{2} - 2 \, c d e^{3} f g + c d^{2} e^{2} g^{2}\right )} x\right )} \sqrt {g x + f}}{d e^{5} f^{2} g - 2 \, d^{2} e^{4} f g^{2} + d^{3} e^{3} g^{3} + {\left (e^{6} f^{2} g - 2 \, d e^{5} f g^{2} + d^{2} e^{4} g^{3}\right )} x}\right ] \]
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Timed out. \[ \int \frac {a+b x+c x^2}{(d+e x)^2 \sqrt {f+g x}} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {a+b x+c x^2}{(d+e x)^2 \sqrt {f+g x}} \, dx=\text {Exception raised: ValueError} \]
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none
Time = 0.28 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.26 \[ \int \frac {a+b x+c x^2}{(d+e x)^2 \sqrt {f+g x}} \, dx=-\frac {{\left (4 \, c d e f - 2 \, b e^{2} f - 3 \, c d^{2} g + b d e g + a e^{2} g\right )} \arctan \left (\frac {\sqrt {g x + f} e}{\sqrt {-e^{2} f + d e g}}\right )}{{\left (e^{3} f - d e^{2} g\right )} \sqrt {-e^{2} f + d e g}} - \frac {\sqrt {g x + f} c d^{2} g - \sqrt {g x + f} b d e g + \sqrt {g x + f} a e^{2} g}{{\left (e^{3} f - d e^{2} g\right )} {\left ({\left (g x + f\right )} e - e f + d g\right )}} + \frac {2 \, \sqrt {g x + f} c}{e^{2} g} \]
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Time = 0.25 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.04 \[ \int \frac {a+b x+c x^2}{(d+e x)^2 \sqrt {f+g x}} \, dx=\frac {\mathrm {atan}\left (\frac {\sqrt {e}\,\sqrt {f+g\,x}}{\sqrt {d\,g-e\,f}}\right )\,\left (a\,e^2\,g-2\,b\,e^2\,f-3\,c\,d^2\,g+b\,d\,e\,g+4\,c\,d\,e\,f\right )}{e^{5/2}\,{\left (d\,g-e\,f\right )}^{3/2}}+\frac {\sqrt {f+g\,x}\,\left (c\,g\,d^2-b\,g\,d\,e+a\,g\,e^2\right )}{\left (d\,g-e\,f\right )\,\left (e^3\,\left (f+g\,x\right )-e^3\,f+d\,e^2\,g\right )}+\frac {2\,c\,\sqrt {f+g\,x}}{e^2\,g} \]
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